TABLE 5.
Fixation and elimination of drug resistance mutations carrying different costs of resistance
| Cost of resistance (%) | No. of generations for:
|
|
|---|---|---|
| Fixation by compensatory mutationa | Eliminationb | |
| 2 | 912 | 1,139 |
| 5 | 359 | 449 |
| 10 | 175 | 218 |
| 20 | 83 | 103 |
Assuming a frequency of 10−6 of a compensatory mutation restoring fitness; the values are the number of generations (t) required for the compensated resistance genotype to become fixed, i.e., to represent 99% of the drug-resistant population, determined by the following formula: t = ln[(rct/rt)/(rct−1/rt−1)]/ln(1 − cost per generation), where rct and rct−1 are absolute numbers of resistant mutants with a compensatory mutation.
Calculated for a ratio of resistant to susceptible organisms of 99:1 at time zero; the values are the number of generations (t) to reach levels of spontaneous drug resistance frequency (10−8) determined by the following formula: t = ln[10−8 (r0/S0)]/ln(1 − cost per generation).